HP Cycle 26

🟢 6: T 2/16, 🔵❗ 8: W 2/17 ↩️ Pivot circular motion lab (1)

Pd 8 QUIZ on ➕ Positive Physics Projectile Motion.

Today, after the Projectile Motion Quiz, we'll talk very briefly about "uniform circular motion." We'll talk about some variables that we can observe regarding an object traveling in a circle at constant speed. Then, we'll start to work on a lab in ↩️ Pivot Interactives called "Forces in Circular Motion." I would recommend dividing the work in taking data - first discuss as a group how you will take the data in each part and come to consensus; then each person take their data. The lab is due on Sunday at at 10pm.

Homework: Finish at least taking data for your part the ↩️ Pivot Interactives lab. Next time, you will have time to share the data with the others in your group so you can analyze the data together and work on the conclusion.

🟩❗ 6: W 2/17, 🟦 8: Th* 2/18 ↩️ Pivot circular motion lab (2)

Pd 6 QUIZ on ➕ Positive Physics Projectile Motion.

Today, we'll start class with a geometric derivation of centripetal acceleration. If you missed class or would like to review the derivation from class, you may watch the video below. We'll use the rest of class time to share data and make conclusions in the lab.

Homework: Finish the ↩️ Pivot Interactives lab by Sunday at 10pm.

Optional Extra Practice: Centripetal Acceleration and Force CompuSheets. ANSWERS.

💚 6: F 2/19, 💙 8: F 2/19 uniform circular motion problems

Today, we'll spend time working through some circular motion example problems:

• car rounding a curve

• rotor ride

• Vertical Circles (extra presentation)

Vertical circles are an example of where gravity combines with some other force to account for the centripetal force. Remember "centripetal force" is another word for NET force when going in a circle.

With any remaining time, you may start ➕ Positive Physics circular motion problems from the next post.

Optional Extra Practice: If you need extra practice on easy UCM problems, Circular Motion Practice worksheet (optional) (Ans: 1. (a) 8.77m/s² (b) mass times 1a. 2. (a) 1.56m/s (b) mass times 8.11m/s² (c) 8.11m/s². 3. (a) 0.650 (b) no change. Hard Circular Motion Problems. (skip #9) ANSWERS. - note: for #3a, an acceleration of “1g” is 9.8 m/s², so an acceleration of 0.050g is (0.050)(9.8 m/s²).

Homework: If you missed class or would like to review, check out these videos on vertical circles: